(x^2+4x-5)/(x^2-1)

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Solution for (x^2+4x-5)/(x^2-1) equation: 


D( x )

x^2-1 = 0

x^2-1 = 0

x^2-1 = 0

1*x^2 = 1 // : 1

x^2 = 1

x^2 = 1 // ^ 1/2

abs(x) = 1

x = 1 or x = -1

x in (-oo:-1) U (-1:1) U (1:+oo)

(x^2+4*x-5)/(x^2-1) = 0

x^2+4*x-5 = 0

x^2+4*x-5 = 0

DELTA = 4^2-(-5*1*4)

DELTA = 36

DELTA > 0

x = (36^(1/2)-4)/(1*2) or x = (-36^(1/2)-4)/(1*2)

x = 1 or x = -5

(x+5)*(x-1) = 0

((x+5)*(x-1))/(x^2-1) = 0

( x+5 )

x+5 = 0 // - 5

x = -5

( x-1 )

x-1 = 0 // + 1

x = 1

x in { 1} 

x = -5

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